MATH SOLVE

3 months ago

Q:
# What are the zeros of the quadratic function f(x) = 6x2 + 12x - 7?β

Accepted Solution

A:

Answer:[tex]f(x) = 6x ^{2} + 12x - 7 \\ x = \frac{ - 6 + \sqrt{78} }{6} \: , - \frac{ - 6 - \sqrt{78} }{6} [/tex]